Example 1
----------

max 3 x1 + 8 x2
subject to
2 x1 + 4 x2 <=1600
6 x1 + 2 x2 <=1800
 x2 <=350
end

----------------------



 LP OPTIMUM FOUND AT STEP      2

        OBJECTIVE FUNCTION VALUE

        1)      3100.000

  VARIABLE        VALUE          REDUCED COST
        X1       100.000000          0.000000
        X2       350.000000          0.000000


       ROW   SLACK OR SURPLUS     DUAL PRICES
        2)         0.000000          1.500000
        3)       500.000000          0.000000
        4)         0.000000          2.000000

 NO. ITERATIONS=       2



-----------------------SENSITIVITY ANALYSIS --------------------

 RANGES IN WHICH THE BASIS IS UNCHANGED:

                           OBJ COEFFICIENT RANGES
 VARIABLE         CURRENT        ALLOWABLE        ALLOWABLE
                   COEF          INCREASE         DECREASE
       X1        3.000000         1.000000         3.000000
       X2        8.000000         INFINITY         2.000000

                           RIGHTHAND SIDE RANGES
      ROW         CURRENT        ALLOWABLE        ALLOWABLE
                    RHS          INCREASE         DECREASE
        2     1600.000000       166.666672       200.000000
        3     1800.000000         INFINITY       500.000000
        4      350.000000        50.000000        50.000000




-----------------------SENSITIVITY ANALYSIS --------------------

 THE TABLEAU

      ROW  (BASIS)         X1        X2  SLK    2  SLK    3  SLK    4
        1 ART           0.000     0.000     1.500     0.000     2.000  3100.000
        2       X1      1.000     0.000     0.500     0.000    -2.000   100.000
        3 SLK    3      0.000     0.000    -3.000     1.000    10.000   500.000
        4       X2      0.000     1.000     0.000     0.000     1.000   350.000