max 8x1+5x2
st
 2x1+  x2 <=1200
 3x1+ 4x2 <=2400
  x1+  x2 <= 800
  x1-  x2 <= 450 
end

------------------- SOLUTION ----------------------------

 LP OPTIMUM FOUND AT STEP      2

        OBJECTIVE FUNCTION VALUE

        1)      5040.000

  VARIABLE        VALUE          REDUCED COST
        X1       480.000000          0.000000
        X2       240.000000          0.000000


       ROW   SLACK OR SURPLUS     DUAL PRICES
        2)         0.000000          3.400000
        3)         0.000000          0.400000
        4)        80.000000          0.000000
        5)       210.000000          0.000000

 NO. ITERATIONS=       2


 RANGES IN WHICH THE BASIS IS UNCHANGED:

                           OBJ COEFFICIENT RANGES
 VARIABLE         CURRENT        ALLOWABLE        ALLOWABLE
                   COEF          INCREASE         DECREASE
       X1        8.000000         2.000000         4.250000
       X2        5.000000         5.666667         1.000000

                           RIGHTHAND SIDE RANGES
      ROW         CURRENT        ALLOWABLE        ALLOWABLE
                    RHS          INCREASE         DECREASE
        2     1200.000000       150.000000       600.000000
        3     2400.000000       400.000000       350.000000
        4      800.000000         INFINITY        80.000000
        5      450.000000         INFINITY       210.000000